Seating Arrangement for Punjab Police SI

Answer: 2 — 18

Number the seats 1, 2, 3, ... from the left end of the row as the persons themselves see it, so "to the right of" means a higher number. - M is at an end with G immediately to M's right, so M must be the left end: M = 1, G = 2. - Only one person sits between G and S, so S = 4. - S is third to the left of Q, so Q = S + 3 = 7. - Only three persons sit between R and Q, so R = 3 or R = 11. If R = 3 then T = R + 4 = 7, which is already Q — impossible. So R = 11. - T is fourth to the right of R: T = 15. U is third to the right of T: U = 18. U therefore occupies seat 18, and since no one else sits in the row, seat 18 is the far end. Total persons = 18. Option 1 (19) is the trap for anyone who adds a seat beyond U; but nothing in the clues places a person to U's right.

Answer: 3 — Three

X is at an end. If X were seat 1, then Y would be seat 4 (two people between them), B = Y − 2 = seat 2, and B and A with two people between them forces A = seat 5; then the gap from A to X would be 4, needing the gap from Y to Z to be 4 as well, i.e. Z at seat 0 or 8 — impossible. So X is at seat 7, Y at seat 4, B at seat 2 and A at seat 5. Now the gap from A to X is 2, so the gap from Y to Z is also 2, giving Z at seat 2 or 6; seat 2 is B, so Z is at seat 6. Seats 1 and 3 are left for C and D, and C cannot be at an end, so C is at seat 3 and D at seat 1. The line is: Seat (left to right)  ·  1  ·  2  ·  3  ·  4  ·  5  ·  6  ·  7 Person  ·  D  ·  B  ·  C  ·  Y  ·  A  ·  Z  ·  X A is at seat 5 and D at seat 1, so seats 2, 3 and 4 (B, C and Y) lie between them — three people. Option 1 (Two) comes from counting only the gap to C.

Answer: 3 — Z

X is at an end. If X were seat 1, then Y would be seat 4 (two people between them), B = Y − 2 = seat 2, and B and A with two people between them forces A = seat 5; then the gap from A to X would be 4, needing the gap from Y to Z to be 4 as well, i.e. Z at seat 0 or 8 — impossible. So X is at seat 7, Y at seat 4, B at seat 2 and A at seat 5. Now the gap from A to X is 2, so the gap from Y to Z is also 2, giving Z at seat 2 or 6; seat 2 is B, so Z is at seat 6. Seats 1 and 3 are left for C and D, and C cannot be at an end, so C is at seat 3 and D at seat 1. The line is: Seat (left to right)  ·  1  ·  2  ·  3  ·  4  ·  5  ·  6  ·  7 Person  ·  D  ·  B  ·  C  ·  Y  ·  A  ·  Z  ·  X Second from the right end is seat 6, which is Z. Option 1 (A) is seat 5, i.e. third from the right.

Answer: 2 — Saransh

Six people fill seats 1 to 6 from left to right. Zeba and Rahul are in the centre, i.e. seats 3 and 4, and Zeba is to the left of Rahul, so Zeba = 3 and Rahul = 4. Aakash and Parul take the ends. Saransh is immediately to the left of Aakash, which is only possible if Aakash = 6 and Saransh = 5; then Parul = 1 and Xylo = 2. Order: Parul, Xylo, Zeba, Rahul, Saransh, Aakash. Between Rahul (4) and Aakash (6) sits Saransh (5). Zeba is on the other side of Rahul, which is the trap.

Answer: 1 — Xylo

The same arrangement holds: Parul, Xylo, Zeba, Rahul, Saransh, Aakash from left to right. Parul is at the left end (seat 1), so the person immediately to her right is at seat 2, which is Xylo. Zeba at seat 3 is two places away, not immediately next.

Answer: 3 — 13

Everyone faces north, so left and right are our left and right. Measure every seat from H. I is immediately right of H, so I = H + 1. I is third to the right of K, so K = I − 3 = H − 2. J = H + 4. Only one person sits between J and L with J on the left, so L = J + 2 = H + 6. M = L + 3 = H + 9. Only two people sit between H and N, so N is either H + 3 or H − 3. N must be at an end, and H + 3 lies between K and M, so N = H − 3. The leftmost named seat is now N, so N is seat 1 and H is seat 4. Then M = H + 9 = seat 13, which is the other end. Seat  ·  Person 1  ·  N 2  ·  K 4  ·  H 5  ·  I 8  ·  J 10  ·  L 13  ·  M The unnamed seats 3, 6, 7, 9, 11 and 12 are the remaining people, so the row holds 13 people in all. Choosing N = H + 3 gives the trap answers, but it puts N inside the row instead of at an end.

Answer: 3 — Priya

Seven people in all (Rahul, Saumya and the five between them), so the row has seats 1–7 and Radhika, being "in the middle", is at seat 4. Everyone faces north, so each person's own right hand points along the row away from Rahul's end. - Reecha is immediately to Rahul's right, so Rahul cannot be at the far end on his own right-hand side — put Rahul at seat 1 and Reecha at seat 2. (Had Rahul been at seat 7, seat 8 would be needed for Reecha.) - Saumya then takes seat 7, and Praveen, immediately to her left, takes seat 6. - Radhika is at seat 4, with Raj and Priya flanking her at seats 3 and 5. Raj is to her left, so Raj is at seat 3 and Priya at seat 5. Seat (Rahul's end → Saumya's end)  ·  Person 1  ·  Rahul 2  ·  Reecha 3  ·  Raj 4  ·  Radhika 5  ·  Priya 6  ·  Praveen 7  ·  Saumya Radhika is at seat 4 and Praveen at seat 6, so the person between them is at seat 5 — Priya. Option 4 (Saumya) is the neighbour on the far side of Praveen, not between the two named people.

Answer: 1 — Raj

Seven people in all (Rahul, Saumya and the five between them), so the row has seats 1–7 and Radhika, being "in the middle", is at seat 4. Everyone faces north, so each person's own right hand points along the row away from Rahul's end. - Reecha is immediately to Rahul's right, so Rahul cannot be at the far end on his own right-hand side — put Rahul at seat 1 and Reecha at seat 2. (Had Rahul been at seat 7, seat 8 would be needed for Reecha.) - Saumya then takes seat 7, and Praveen, immediately to her left, takes seat 6. - Radhika is at seat 4, with Raj and Priya flanking her at seats 3 and 5. Raj is to her left, so Raj is at seat 3 and Priya at seat 5. Seat (Rahul's end → Saumya's end)  ·  Person 1  ·  Rahul 2  ·  Reecha 3  ·  Raj 4  ·  Radhika 5  ·  Priya 6  ·  Praveen 7  ·  Saumya Reecha is at seat 2 and Radhika at seat 4, so the person between them is at seat 3 — Raj. Option 2 (Rahul) is on the other side of Reecha, at seat 1.

Answer: 1 — 15

Everyone faces north, so left and right in the clues are the ordinary left and right of the drawn row. Put C at position 0 and number seats rightwards. - B is fourth to the left of C → B = −4. - D is second to the right of C → D = +2. - G is third to the right of D → G = +5. - F is second to the right of G → F = +7. - E is immediately left of A → E = A − 1. - Exactly one person sits between A and B → A = B ± 2 = −2 or −6. If A = −2 then E = −3, but B at −4 would sit further left, so E could not be at an end. So A = −6 and E = −7. The row therefore runs from E at −7 to F at +7, and F is the far right end as required. Seats −7 to +7 inclusive is 7 + 7 + 1 = 15 people. Option 2 (14) is what you get by forgetting to count position 0 itself.

Answer: 1 — P

Number the seats 1 to 7 from the left. - "Third to the left of P is at an end" forces P − 3 = 1, so P sits at 4. - "Q is fourth to the right of S" with R immediately right of Q allows S at 1 (Q at 5, R at 6) or S at 2 (Q at 6, R at 7). If S were at 2, O would have to sit next to P at 3 or 5 with N on its other side — but those seats are S and Q. So S is at 1, Q at 5, R at 6. - O is between N and P, so N-O-P runs 2-3-4, and M takes the last free seat, 7. ```puzzle:row row (N): S, N, O, P, Q, R, M ``` O is at seat 3 and Q at seat 5, so the only person between them is the occupant of seat 4, P. R (option 3) sits beyond Q at 6 and S (option 4) is at the far left end. Option 2 names Q itself.

Answer: 4 — 19

Number the seats 1, 2, 3 … from the extreme left; facing north means left and right are the reader's left and right. R is second from the left end, so R = 2. Two people sit between R and N. N cannot be to R's left (only seat 1 is there), so N = 5. T is seventh to the right of N: T = 5 + 7 = 12. M is exactly midway between R and T: M = (2 + 12)/2 = 7. One person sits between T and P, so P = 10 or P = 14. P is second to the left of S, so S = P + 2. P = 10 would force S = 12, which is T's seat, so P = 14 and S = 16. O is third to the right of S: O = 19. Q is immediately to O's left: Q = 18. The rightmost seat used is 19 and nothing is stated beyond it, so the row has 19 people: R(2), N(5), M(7), T(12), P(14), S(16), Q(18), O(19).

Answer: 3 — K

Number the seats 1 to 7 from the left. B is third from one end. If B = 3 then A = 5 and M is 4 or 6; M = 4 makes C = 4 as well (three people sit right of M, so three must sit left of C), and M = 6 leaves no seat pair for 'J second to the right of K'. So that branch dies. Take B = 5 (third from the right end). Then A = 7 and M, an immediate neighbour of A, is 6. Only one person (seat 7) sits to the right of M, so only one sits to the left of C: C = 2. Seats 1, 3, 4 are left for J, K, L, and J two to the right of K forces K = 1, J = 3, leaving L = 4. Final line, left to right: K, C, J, L, B, M, A. Seat 1 is K, so K sits at the extreme left end. M sits at seat 6 and C at seat 2, so both are far from the end.

Answer: 1 — A and J

Number the seats 1 to 7 from the left. B is third from one end. If B = 3 then A = 5 and M is 4 or 6; M = 4 makes C = 4 as well (three people sit right of M, so three must sit left of C), and M = 6 leaves no seat pair for 'J second to the right of K'. So that branch dies. Take B = 5 (third from the right end). Then A = 7 and M, an immediate neighbour of A, is 6. Only one person (seat 7) sits to the right of M, so only one sits to the left of C: C = 2. Seats 1, 3, 4 are left for J, K, L, and J two to the right of K forces K = 1, J = 3, leaving L = 4. Final line, left to right: K, C, J, L, B, M, A. K is at seat 1 and B at seat 5, so seats 2, 3, 4 lie between them — three people. Now test the options on the same line: A(7) and J(3) have seats 4, 5, 6 between them — three people, a match. C(2) and L(4) have only one person between them, M(6) and B(5) none, and K(1) and A(7) five.

Answer: 3 — 10

Number the seats from the left end of the row, counting towards everyone's right. E is at the immediate left of A, so E cannot be at the right-hand end; E therefore takes the left end, seat 1, and A takes seat 2. D must then be at the other end, so D is the last seat. One person sits between A and B, so B is two seats from A: B = 4 (B = 0 does not exist). C is fourth to the right of B, so C = 4 + 4 = 8. One person sits between C and D, so D = 6 or D = 10. D = 6 is impossible because C already sits at 8 and D is the end seat, so D = 10 and the row has 10 seats. Seat  ·  1  ·  2  ·  3  ·  4  ·  5  ·  6  ·  7  ·  8  ·  9  ·  10 Person  ·  E  ·  A  ·  —  ·  B  ·  —  ·  —  ·  —  ·  C  ·  —  ·  D The five named people plus five unnamed seat-holders make 10 in all. 12 is the trap for anyone who puts E at the right end and runs the row the other way.

Answer: 3 — 10

Everyone faces north, so for the reader left means west and right means east; draw the row west to east. M and F are at the two extreme ends. Y sits immediately to M's right, so M cannot be at the right-hand end — M is at seat 1 and F is at the far end. Only four people sit between S and M, so S is at seat 6 (M at 1, four people at 2-5, S at 6). Exactly three people sit between S and F, so F is three seats beyond S plus one, i.e. seat 10. That makes the row ten seats long, which fits 'F occupies an extreme end'. E is third to the left of F, so E is at seat 7 — a free seat, so there is no clash. The row is: M(1) Y(2) _(3) _(4) _(5) S(6) E(7) _(8) _(9) F(10). Total seated = 10.

Answer: 1 — 15

Everyone faces north, so 'left' is the reader's left. Number the seats 1 … n from the left. G is fifth to the left of M, so G is left of M; since G and F hold the two ends, G = 1 and F = n. Then M = 1 + 5 = 6 and Y = 7 (immediately right of M). 'Only four people sit between S and M' means |S − M| = 5, so S = 1 or S = 11; seat 1 is G, so S = 11. 'Exactly three people sit between S and F' means |S − F| = 4, so F = 11 + 4 = 15 (F cannot be 7, that is Y). Check E: third to the left of F gives E = 15 − 3 = 12, a free seat. Everything holds. So the row runs to seat 15 and the total is 15. ```puzzle:row G, _, _, _, _, M, Y, _, _, _, S, E, _, _, F ``` 16 is the trap for anyone who counts the gaps rather than the seats.

Answer: 2 — Two

Fix the line from the clues. A is third from the left, so A = 3. One person between A and B puts B at 1 or 5. Try B = 1. Three people between B and X gives X = 5. Two people between X and Y gives Y = 2 (Y = 8 does not exist). One person then sits to the left of Y, so one person must sit to the right of D, which puts D at 6. C cannot take an end, so C = 4 and Z = 7. Try B = 5 instead: X = 1, Y = 4, and three people sit left of Y, which would force D into seat 4 as well — a clash. So the first line is the only one. ```puzzle:row B, Y, A, C, X, D, Z ``` Now rewrite the line alphabetically: A, B, C, D, X, Y, Z. Seat  ·  Actual  ·  Alphabetical 1  ·  B  ·  A 2  ·  Y  ·  B 3  ·  A  ·  C 4  ·  C  ·  D 5  ·  X  ·  X 6  ·  D  ·  Y 7  ·  Z  ·  Z Only seats 5 (X) and 7 (Z) match, so two positions stay unchanged. 'One' is the trap if you spot Z at the end and stop looking.

Answer: 1 — None

Fix the line from the clues. A is third from the left, so A = 3. One person between A and B puts B at 1 or 5. Try B = 1. Three people between B and X gives X = 5. Two people between X and Y gives Y = 2 (Y = 8 does not exist). One person then sits to the left of Y, so one person must sit to the right of D, which puts D at 6. C cannot take an end, so C = 4 and Z = 7. Try B = 5 instead: X = 1, Y = 4, and three people sit left of Y, which would force D into seat 4 as well — a clash. So the first line is the only one. ```puzzle:row B, Y, A, C, X, D, Z ``` A is on seat 3 and C is on seat 4, so they are neighbours and nobody sits between them. 'One' is the tempting answer if you place C at seat 5 by forgetting that seat 5 is taken by X.

Answer: 4 — 14

Everyone faces north, so a person's left is the west side of the row. Number the seats 1, 2, 3, ... from the left (west) end. G is fourth to the left of E, so G = E − 4; since G must therefore be the smaller number and G sits at an end, G takes seat 1 and E takes seat 5. E is immediately to the left of A, so A = 6. A is to the left of B with exactly one person between them, so B = 8. C is fourth to the right of B, so C = 12. Exactly one person sits between C and D, so D = 10 or 14; D occupies the other end, and the end must lie beyond C, so D = 14. Seat from the left end  ·  Person 1  ·  G 5  ·  E 6  ·  A 8  ·  B 12  ·  C 14  ·  D The row runs from seat 1 to seat 14, so 14 persons are seated. 13 is the trap for anyone who places D at seat 10 and forgets that D has to be at an end past C.

Answer: 2 — G

Place seven seats, numbered 1 to 7 from the leftmost end. E is at the second place from the leftmost end, so E = 2. E is to the immediate left of F, so F = 3, and G is to the immediate right of F, so G = 4. D is at the rightmost end, so D = 7. H and D are the neighbours of I, so I sits between H and D. With D = 7 this forces I = 6 and H = 5. Only J is left, so J = 1. The row is J, E, F, G, H, I, D. ```puzzle:row row (N): J, E, F, G, H, I, D ``` With seven seats the middle is seat 4, which is G. F (option 4) is one seat to its left and H (option 3) one seat to its right, so both are the common near-miss answers.

Answer: 1 — E

Place seven seats, numbered 1 to 7 from the leftmost end. E is at the second place from the leftmost end, so E = 2. E is to the immediate left of F, so F = 3, and G is to the immediate right of F, so G = 4. D is at the rightmost end, so D = 7. H and D are the neighbours of I, so I sits between H and D. With D = 7 this forces I = 6 and H = 5. Only J is left, so J = 1. The row is J, E, F, G, H, I, D. ```puzzle:row row (N): J, E, F, G, H, I, D ``` J is at seat 1, the leftmost end, so the person to his immediate right is the occupant of seat 2, which is E. F (option 4) is two seats away, not immediately next to J.

Answer: 4 — 13

All face north, so left and right are as drawn. B is at an end and immediately left of K, so B is seat 1 and K seat 2. One person sits between K and Q, so Q is seat 4 (seat 0 does not exist). D neighbours both Q and P: D cannot be seat 3 (its neighbours would be K and Q), so D is seat 5 and P seat 6. S is immediately right of P, so S is seat 7; J neighbours both S and M, so J is seat 8 and M seat 9. R is second to the right of M, so R is seat 11; O is second to the right of R, so O is seat 13. ```puzzle:row row (N): B, K, ?, Q, D, P, S, J, M, ?, R, ?, O ``` The row runs from seat 1 to seat 13, the three '?' seats being the unnamed people the first line of the question allows for. Total seated = 13. Counting only the ten named people gives 10, which is why option 3 is the trap.

Answer: 4 — 2nd from the left

P is on the left end, so P is seat 1. N is second from the right, so N is seat 4. N sits next to O, so O is seat 3 or seat 5; L sits with N, so L is seat 3 or seat 5. If O were seat 3, L would be seat 5 and M, who sits next to L, would have to be seat 4, which is N. So O is seat 5 and L is seat 3. M then sits next to L at seat 2, which also satisfies 'L is to the right of M and P', and O at seat 5 is not next to P at seat 1. ```puzzle:row row (N): P, M, L, N, O ``` M sits at seat 2 counted from the left, i.e. 2nd from the left (and 4th from the right). Option 2 is the trap for anyone who counts from the wrong end.

Answer: 3 — N

P is on the left end, so P is seat 1. N is second from the right, so N is seat 4. N sits next to O, so O is seat 3 or seat 5; L sits with N, so L is seat 3 or seat 5. If O were seat 3, L would be seat 5 and M, who sits next to L, would have to be seat 4, which is N. So O is seat 5 and L is seat 3. M then sits next to L at seat 2, which also satisfies 'L is to the right of M and P', and O at seat 5 is not next to P at seat 1. ```puzzle:row row (N): P, M, L, N, O ``` L is at seat 3 and O at seat 5, so the person between them is at seat 4, which is N. M sits on the other side of L, at seat 2, which is why option 4 tempts.

Answer: 1 — 12

Build the chain from left (west) to right (east). R is second to the right of M and O is second to the right of R, so M _ R _ O. Only J sits between S and M, and S has P immediately to its left, so the block must read P S J M (the alternative M J S would put J, not P, next to S). That gives P S J M _ R _ O. Only D sits between Q and P, and P already has S on its right, so Q D P sits on the left. Finally only one person sits between K and Q, and the seat two to the right of Q is already P, so K must be two seats to the left of Q. The row is K _ Q D P S J M _ R _ O: nine named people plus three unnamed gap-seats = 12. Option 2's 11 comes from missing one of the three gap seats. Hence option 1. The seating reads: K – ? – Q – D – P – S – J – M – ? – R – ? – O, where ? marks an unnamed person.

Answer: 2 — (U, X)

Fix the rows as seen by us with north at the top, so that for the north-facing row 2 left is our left, while for the south-facing row 1 left is our right. X faces the girl third to the left of L, and in a row of four only L at our position 1 allows a girl three places to her left, so L is at 1 and X at 4. V sits second to the left of X, so V is at 2, and L faces the girl immediately left of V, i.e. position 1 — consistent. U and W take 1 and 3. N faces the girl second to the right of U, so N = U + 2; only U at 1 keeps N inside the row, giving U at 1, W at 3 and N at 3. M sits second to the left of O in row 1, i.e. two places to our right of O, so O is at 2 and M at 4. Position (our left to right)  ·  1  ·  2  ·  3  ·  4 Row 2, facing north  ·  U  ·  V  ·  W  ·  X Row 1, facing south  ·  L  ·  O  ·  N  ·  M The ends of row 2 are U and X, and the ends of row 1 are L and M. Of the four options only (U, X) is such a pair. (M, O) and (L, N) each mix an end seat with an inner seat, and (U, W) puts two row-2 girls together of whom W is inner.

Answer: 1 — N

Fix the rows as seen by us with north at the top, so that for the north-facing row 2 left is our left, while for the south-facing row 1 left is our right. X faces the girl third to the left of L, and in a row of four only L at our position 1 allows a girl three places to her left, so L is at 1 and X at 4. V sits second to the left of X, so V is at 2, and L faces the girl immediately left of V, i.e. position 1 — consistent. U and W take 1 and 3. N faces the girl second to the right of U, so N = U + 2; only U at 1 keeps N inside the row, giving U at 1, W at 3 and N at 3. M sits second to the left of O in row 1, i.e. two places to our right of O, so O is at 2 and M at 4. Position (our left to right)  ·  1  ·  2  ·  3  ·  4 Row 2, facing north  ·  U  ·  V  ·  W  ·  X Row 1, facing south  ·  L  ·  O  ·  N  ·  M W stands at position 3 of row 2, and the girl at position 3 of row 1 is N, so N faces W. L faces U, O faces V and M faces X, which rules out the other three options.

Answer: 1 — (P, R)

Number the four seats 1 to 4 from west to east. The first row faces south, so for them left is east and right is west; the second row faces north, so for them left is west and right is east. 'R faces the one third to the left of M' needs three seats west of M, so M sits at 4 and R faces seat 1, i.e. R sits at 1. 'P is third to the left of R' puts P three seats towards R's left (east), so P sits at 4, leaving seats 2 and 3 for S and Q. 'Exactly between M and N' means one seat lies between them, so N sits at 2 and that middle person is at seat 3; Q faces him, so Q sits at 3 and S at 2. Finally 'X faces the one to the immediate right of S' — S at seat 2 faces south, so his right is seat 1 — puts X at seat 1 and O at seat 3. Seat (west to east)  ·  1  ·  2  ·  3  ·  4 Row 1, facing south  ·  R  ·  S  ·  Q  ·  P Row 2, facing north  ·  X  ·  N  ·  O  ·  M The first row runs R, S, Q, P, so its two extreme seats are held by R and P — the pair (P, R). Option 4 (O, X) is the trap: X is at one end of the second row but O sits at seat 3, not at an end; the ends of that row are X and M.

Answer: 3 — S

Number the four seats 1 to 4 from west to east. The first row faces south, so for them left is east and right is west; the second row faces north, so for them left is west and right is east. 'R faces the one third to the left of M' needs three seats west of M, so M sits at 4 and R faces seat 1, i.e. R sits at 1. 'P is third to the left of R' puts P three seats towards R's left (east), so P sits at 4, leaving seats 2 and 3 for S and Q. 'Exactly between M and N' means one seat lies between them, so N sits at 2 and that middle person is at seat 3; Q faces him, so Q sits at 3 and S at 2. Finally 'X faces the one to the immediate right of S' — S at seat 2 faces south, so his right is seat 1 — puts X at seat 1 and O at seat 3. Seat (west to east)  ·  1  ·  2  ·  3  ·  4 Row 1, facing south  ·  R  ·  S  ·  Q  ·  P Row 2, facing north  ·  X  ·  N  ·  O  ·  M N sits at seat 2 of the second row, and seat 2 of the first row is S, so S faces N. Q (option 4) faces O, not N — that is the usual slip, because O is the person sitting between M and N.

Answer: 1 — If the data in both statements I and II together are necessary to answer the question

Number the six seats 1 to 6 going anticlockwise, so that for people facing the centre 'one place to the left' means the next higher number. Statement I alone fixes only three people relative to one another: Kishor = Anshul + 2 and Monu = Kishor + 2, so reading round the circle they sit Anshul, _, Kishor, _, Monu. Vedant is not placed at all, so the seat third to his left cannot be named — I alone is not sufficient. Statement II alone gives Shyam = Monu − 1 and Vedant = Shyam + 2 = Monu + 1. Putting Monu at seat 1, Shyam is at 6 and Vedant at 2, and the seat third to Vedant's left is seat 5 — but Kishor, Sonu and Anshul are still free to occupy seats 3, 4 and 5 in any order, so the occupant of seat 5 is unknown. II alone is not sufficient either. Together they settle it. From II, Monu is at 1 and Vedant at 2. From I, Anshul = Monu + 2 = 3 and Kishor = Monu + 4 = 5, leaving Sonu at 4. Third to Vedant's left is seat 5, which is Kishor. Both statements are therefore needed, which rules out options 3 and 4, and since a unique answer does emerge, option 2 is wrong as well.

Answer: 4 — T

Number the eight chairs clockwise, as seen from above with North at the top: 1 and 2 on the North side (both face South), 3 and 4 on the East side (both face West), 5 and 6 on the South side (both face North), 7 and 8 on the West side (both face East). T and W face North, so they hold the two South-side chairs, 5 and 6. For someone facing North the left hand points West, and chair 6 is the western one, so T = 6 and W = 5. R and V face West, so they hold the East-side chairs 3 and 4; V must be next to W (chair 5), and the neighbour of chair 5 on that side is chair 4, so V = 4 and R = 3. Q and S take the West-side chairs 7 and 8. P faces South, so P is on the North side (chair 1 or 2), and P must touch Q — only chair 1 touches a West-side chair, so P = 1 and Q = 8, leaving S = 7 and U = 2. Chair  ·  Side  ·  Facing  ·  Person 1  ·  North (West chair)  ·  South  ·  P 2  ·  North (East chair)  ·  South  ·  U 3  ·  East (North chair)  ·  West  ·  R 4  ·  East (South chair)  ·  West  ·  V 5  ·  South (East chair)  ·  North  ·  W 6  ·  South (West chair)  ·  North  ·  T 7  ·  West (South chair)  ·  East  ·  S 8  ·  West (North chair)  ·  East  ·  Q Everyone faces the centre, so each person's right hand points anticlockwise round the table: the order to a person's right is 1 → 8 → 7 → 6 → 5 → 4 → 3 → 2, that is P, Q, S, T, W, V, R, U. S sits on the West side facing East, so S's right hand points South. Moving South from S's chair takes you round the corner to the West chair of the South side, which is T. So T is to the immediate right of S. Q is on S's immediate left (to the North), which is the tempting wrong answer.

Answer: 3 — Two

Number the eight chairs clockwise, as seen from above with North at the top: 1 and 2 on the North side (both face South), 3 and 4 on the East side (both face West), 5 and 6 on the South side (both face North), 7 and 8 on the West side (both face East). T and W face North, so they hold the two South-side chairs, 5 and 6. For someone facing North the left hand points West, and chair 6 is the western one, so T = 6 and W = 5. R and V face West, so they hold the East-side chairs 3 and 4; V must be next to W (chair 5), and the neighbour of chair 5 on that side is chair 4, so V = 4 and R = 3. Q and S take the West-side chairs 7 and 8. P faces South, so P is on the North side (chair 1 or 2), and P must touch Q — only chair 1 touches a West-side chair, so P = 1 and Q = 8, leaving S = 7 and U = 2. Chair  ·  Side  ·  Facing  ·  Person 1  ·  North (West chair)  ·  South  ·  P 2  ·  North (East chair)  ·  South  ·  U 3  ·  East (North chair)  ·  West  ·  R 4  ·  East (South chair)  ·  West  ·  V 5  ·  South (East chair)  ·  North  ·  W 6  ·  South (West chair)  ·  North  ·  T 7  ·  West (South chair)  ·  East  ·  S 8  ·  West (North chair)  ·  East  ·  Q Everyone faces the centre, so each person's right hand points anticlockwise round the table: the order to a person's right is 1 → 8 → 7 → 6 → 5 → 4 → 3 → 2, that is P, Q, S, T, W, V, R, U. P sits on the North side facing South, so P's right hand points West. Going in that direction the order is P → Q → S → T. The people strictly between P and T on that side are Q and S, so the count is Two. Counting the other way round the table (P → U → R → V → W → T) gives Five, which is the trap that option 1 is built on.

Answer: 3 — North-East

D faces exactly north, so D occupies the south seat and everyone faces the centre of the table. For a person facing the centre, his right hand points clockwise-backwards, so 'immediately to the right' is the next seat anticlockwise on the compass. E is at the north seat. A is immediately to E's right, so A is at north-west; F is immediately to E's left, so F is at north-east. D is at south; G immediately to his right is south-east, H immediately to his left is south-west. C is second to D's left: first left is south-west (H), second left is west, so C is at west. B opposite C is then east — consistent with the last clue, which confirms the whole arrangement. Seat (compass position at the table)  ·  Person North  ·  E North-East  ·  F East  ·  B South-East  ·  G South  ·  D South-West  ·  H West  ·  C North-West  ·  A F sits at the north-east seat. North-west is the trap: that is A's seat, not F's.

Answer: 2 — Three

Use the arrangement established from the same data: Seat (compass position at the table)  ·  Person North  ·  E North-East  ·  F East  ·  B South-East  ·  G South  ·  D South-West  ·  H West  ·  C North-West  ·  A Start at D (south) and move along D's left, that is south-west, west, north-west, north: the seats passed are H (south-west), C (west) and A (north-west) before reaching E at north. That is three persons. Counting the other way round (D's right: G, B, F) would also give three, but the four-person answer comes from wrongly including E itself, and 'two' from starting the count one seat late.

Answer: 1 — North-West

Everyone faces the centre, so eight chairs sit at the eight compass points. E is at North, and for a person at North facing the centre the right hand points west: A (immediate right of E) takes North-West and F (immediate left) takes North-East. D faces exact North, so D occupies the South chair; his immediate right is South-East (G) and his immediate left is South-West (H). Second to D's left from South-West is West, so C is at West, and B, directly opposite C, is at East. Final seating — North: E, North-East: F, East: B, South-East: G, South: D, South-West: H, West: C, North-West: A. A sits to the immediate right of E, and since E at North faces the centre (southwards) his right hand side is the West side, so A is at North-West. North-East (option 3) is F's seat, because F is on E's left.