1208.The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is#
- A55%
- B33%
- C22%
- D44%
All 16 Mensuration questions the Punjab PSC asked between 2019 and 2025, each with a worked answer and the exam it came from. First 10 free to read.
1 of these 16 were set in more than one exam — the Commission reuses this topic, which is the argument for working through it rather than skimming it.
Free to read, with the worked answer and the exam each one came from. The book prints this topic in the order the Commission favours, so these are the ones to know first.
If each side grows by 20%, the new area is 1.2 × 1.2 = 1.44 times the old area, an increase of 44%. > New area = (1.2l)(1.2b) = 1.44 lb > Increase = 44% Shortcut: a + b + ab/100 = 20 + 20 + 4 = 44%.
Work everything in cubic centimetres. > Milk wanted = π × 80² × 120 = 768000π > One bucket holds π × 20² × 30 = 12000π, but only 90% of it reaches the drum = 10800π > 768000 ÷ 10800 = 71.1 He needs about 71 buckets.
Apply E = sqrt(a/6) to each cube. > a = 1350: E = sqrt(1350/6) = sqrt(225) = 15 > a = 600: E = sqrt(600/6) = sqrt(100) = 10 > Difference = 15 − 10 = 5. The formula follows from a cube's surface area being 6E².
The housefly takes the space diagonal. The bug's shortest surface route unfolds two faces into a 3 m × 6 m rectangle. > Fly: sqrt(3² + 3² + 3²) = 3·sqrt(3) ≈ 5.20 m > Bug: sqrt(3² + 6²) = sqrt(45) ≈ 6.71 m Both distances exceed 5 m whatever the speeds, so (b) is definitely correct. (a) fails if the fly is slow enough. (c) gives 6.71/3 ≈ 2.24 s for the bug against 5.20 s for the fly. (d) fails because at equal speeds the fly's round trip of 10.39 m takes longer than the bug's 6.71 m.
Length of the wire = 12 squares × perimeter 16 cm = 192 cm. Each 5 cm × 1 cm rectangle has perimeter 2(5 + 1) = 12 cm. > Number of rectangles = 192 ÷ 12 = 16 So 16 rectangles use the wire exactly.
One jam ball has radius 1 cm. Volume = (4/3)π r³ = (4/3) × 3.14 × 1 ≈ 4.19 cm³. > Daily jam = 20 × 4.19 ≈ 83.8 cm³ > Each cube of side 1 cm = 1 cm³ > Cubes needed ≈ 83.8 → 84 (nearest whole number) So Pikachu was fed about 84 cubes of jam that day.
> Clay = 9 spheres = 9 × (4/3)πr³ = 12πr³ > One cylinder: height = 2r, so volume = πr² × 2r = 2πr³ > Number of cylinders = 12πr³ ÷ 2πr³ = 6 The same clay makes 6 cylinders.
First find the speed from the circumference of the circle, then apply it to the perimeter of the hexagon. > Circumference of the circle = 2 × (22/7) × 21 = 132 metres → speed = 132/44 = 3 metres/second > Perimeter of the hexagon = 6 × 42 = 252 metres > Time = 252/3 = 84 seconds
> Perimeter of square = 4 x side > side = 32 / 4 = 8 Each side of the square is 8 cm.
Circumference = 2πr and area = πr²; πr² > 2πr only when r > 2. At r = 2 the two become equal (4π) and at r < 2 the area is smaller than the circumference (for example r = 1: area π, circumference 2π). So the area is greater than the circumference except when r ≤ 2. (a) is wrong because at r = 2 the two are equal; (b) and (c) are proved wrong for r = 1.5 (area 2.25π < circumference 3π).
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See the printed book →The Commission set 16 Mensuration questions across 17 papers between 2019–2025. That is the whole set, not a sample — every one of them is in the book, and the 10 most-asked are on this page free.
Yes. 1 of these 16 were set in more than one exam, which is why they are worth working rather than reading. Each question here carries a badge showing how many sittings asked it.
Here. Every question on this page is a solved MCQ: the four options as printed, the correct answer, and a worked explanation in plain English — not just a letter. The rest of the 16 are in the book, in the same form.
Switch to Attempt mode at the top of the questions. You get one question at a time and it is marked the moment you pick an option, with the reason underneath — the same way the exam feels, on your phone.
The questions are on screen rather than in a downloadable file, so they stay current and correct. The printed book has all 16 of these plus the rest of the Reasoning & Aptitude section, and every buyer gets the whole thing online as well.
The exams behind these questions, most first. A paper here is a sitting: a question set in two papers of the same sitting counts once.
| Exam | Year | Questions |
|---|---|---|
| Naib Tehsildar | 2023 | 2 |
| Assistant Director Assistant Controller of Stores St | 2022 | 2 |
| Remote Sensing and Geographic Information System Officer (Group-B) | 2025 | 1 |
| Punjab Civil Services (Prelims) — CSAT | 2025 | 1 |
| Superintendent Home (Group-B) | 2024 | 1 |
| District Social Security Officer (Group-B) | 2024 | 1 |
| Principal, Industrial Training Institute (Women) | 2024 | 1 |
| Junior Auditor (Group B) | 2024 | 1 |
| District Manager (Group-B) in Punjab State Warehousing Corporation Under the Dep | 2024 | 1 |
| District Defence Services Welfare Officer | 2023 | 1 |
| Assistant Town Planner (Group A) | 2023 | 1 |
| Assistant District Attorney (Group-B) | 2022 | 1 |