All 74 Series questions the Punjab PSC asked between 2015 and 2026, each with a worked answer and the exam it came from. First 10 free to read.
17 of these 74 were set in more than one exam — the Commission reuses this topic, which is the argument for working through it rather than skimming it.
Free to read, with the worked answer and the exam each one came from. The book prints this topic in the order the Commission favours, so these are the ones to know first.
Find the next number in the series
The terms alternate between cubes and squares of consecutive numbers. > 13, 22, 33, 42, 53, 62, 73 > Missing term = 53 = 125 So (b).
The differences between the terms are 0, 3, 8, 15. These are 1² − 1, 2² − 1, 3² − 1, 4² − 1. So the next difference is 5² − 1 = 24. > 2 → 2 (+0) → 5 (+3) → 13 (+8) → 28 (+15) > 28 + 24 = 52 So the missing term is 52.
The series adds and multiplies by turns, with a counter that grows: +1, ×1, +2, ×2, +3, ×3, +4, ×4, +5. > 2 + 1 = 3, 3 × 1 = 3, 3 + 2 = 5, 5 × 2 = 10, 10 + 3 = 13 > 13 × 3 = 39, 39 + 4 = 43, 43 × 4 = 172, 172 + 5 = 177 The missing term is 39.
Each new term is the current number written in front of the previous term: 2 → 25, 3 → 325, 4 → 4325. > 5 = 5 followed by 4325 = 54325
Read the matrix as four rows of three: (3, 8, 10), (2, ?, 1), (6, 56, 90), (2, 20, 0). Each number in the third row is n × (n − 1) of the number above it in the first row. Each number in the fourth row is n × (n − 1) of the number in the second row. > 3×2 = 6, 8×7 = 56, 10×9 = 90 > 2×1 = 2, ? × (? − 1) = 20 → ? = 5, 1×0 = 0 So the missing number is 5.
Read the 16 entries as a 4 × 4 table. Every complete row adds up to the same total. > 1 + 3 + 2 + 9 = 15; 2 + 3 + 8 + 2 = 15; 8 + 2 + 2 + 3 = 15 > p + 7 + 3 + 1 = 15 → p = 4 So (b). (Reading column-wise gives the same. There 3 + 7 + 3 + 2, 2 + 3 + 8 + 2 and 9 + 1 + 2 + 3 all give 15. That leaves 1 + p + 2 + 8 = 15.)
Each term is one less than a perfect cube: 1³ − 1 = 0, 2³ − 1 = 7, 3³ − 1 = 26, … 9³ − 1 = 728. > Next term = 10³ − 1 = 999 So (d).
Multiply each term by a rising number, then add one less than that multiplier. > 3 × 2 + 1 = 7 > 7 × 3 + 2 = 23 > 23 × 4 + 3 = 95 > 95 × 5 + 4 = 479 So the next term is 479.
Each term is a cube minus 1. > 2³ − 1 = 7, 3³ − 1 = 26, 4³ − 1 = 63, 5³ − 1 = 124, 6³ − 1 = 215, 7³ − 1 = 342 > Next: 8³ − 1 = 512 − 1 = 511 The next number is 511.
Each term is four times the previous term minus 1. > 2 × 4 − 1 = 7, 7 × 4 − 1 = 27, 27 × 4 − 1 = 107, 107 × 4 − 1 = 427 > 427 × 4 − 1 = 1707 So (b).
You have read the ten the Commission asks most. The rest of this topic — and all 4,239 questions across the book, each with a worked solution — come with either edition.
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See the printed book →The Commission set 74 Series questions across 69 papers between 2015–2026. That is the whole set, not a sample — every one of them is in the book, and the 10 most-asked are on this page free.
Yes. 17 of these 74 were set in more than one exam, which is why they are worth working rather than reading. Each question here carries a badge showing how many sittings asked it.
Here. Every question on this page is a solved MCQ: the four options as printed, the correct answer, and a worked explanation in plain English — not just a letter. The rest of the 74 are in the book, in the same form.
Switch to Attempt mode at the top of the questions. You get one question at a time and it is marked the moment you pick an option, with the reason underneath — the same way the exam feels, on your phone.
The questions are on screen rather than in a downloadable file, so they stay current and correct. The printed book has all 74 of these plus the rest of the Reasoning & Aptitude section, and every buyer gets the whole thing online as well.
The exams behind these questions, most first. A paper here is a sitting: a question set in two papers of the same sitting counts once.
| Exam | Year | Questions |
|---|---|---|
| Extra Assistant Conservator of Forests in the the Department of Forest and Wild | 2019 | 7 |
| One Hundred Eighteen Posts | 2017 | 7 |
| Senior Scientific Officer (Food Safety) Microbiology | 2018 | 6 |
| Senior Scientific Officer (Drugs) | 2018 | 6 |
| Assistant Director, Industrial Training Principal Junior Scale Industrial Traini | 2018 | 6 |
| Enquiry Officer | 2018 | 6 |
| Drugs Control Officer | 2018 | 6 |
| Legal Assistant | 2019 | 4 |
| Research Officer | 2019 | 4 |
| Technical Assistants | 2019 | 4 |
| Network Engineer | 2019 | 4 |
| Superintendent Home | 2019 | 4 |